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NVIDIA Dory 4B lets one model run at four different compute budgets by repeating middle layers, offering flexible performance without retraining.
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NVIDIA Dory 4B lets one model run at four different compute budgets by repeating middle layers, offering flexible performance without retraining.
AI-generated summary. Check the original reporting for context and accuracy.
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In this tutorial, we work with Dory 1.0 4B, a small reasoning model from NVIDIA’s Nemotron Labs whose middle layers form a shared block that can be applied once, twice, three, or four times for every token. Each extra pass, or loop, spends more computation per token without adding a single parameter, so one checkpoint can run at four different compute budgets with no retraining. We build the llama.cpp branch that NVIDIA’s model card pins, download the 3.7 GB GGUF, and read the architecture straight from the file to predict what each loop should cost in parameters and cache memory. We then check those predictions against the running server, measure decode speed at every loop count, test whether the cheaper last-loop cache changes the model’s predictions, and run a paired GSM8K evaluation to see how accuracy, answer length, and time per solved question move as the loops increase. Copy CodeCopiedUse a different Browserimport os import re import sys import json import time import math import random import signal import shutil import hashlib import platform import statistics import traceback import subprocess import collections import urllib.request from pathlib import Path RESULTS = {} # step -> one-line result, for the summary table CLAIMS = [] # (step, claim, held) CURRENT = ["1"] def banner(title): print("\n" + "=" * 78) print(title) print("=" * 78) def section(name): def wrap(fn): def run(*a, **kw): CURRENT[0] = name.split(".")[0] banner(name) t0 = time.time() try: out = fn(*a, **kw) RESULTS[name] = out if isinstance(out, str) else "ok" return out except Exception as e: RESULTS[name] = f"SKIPPED / FAILED -> {type(e).__name__}: {e}" print(f"\n[!] {name} did not complete: {type(e).__name__}: {e}") traceback.print_exc(limit=3) return None
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